ICT
BASED LESSON TEMPLATE
Name of the teacher : Arya C.S Date
:
Name of the School :MGHSS
KANIYAPURAM Class :VIII
Subject : Mathematics Division:
Unit : ]Whn\nabw Period
:
Topic :]mZhmÀjnIw Duration :
Curricular Statement
Bibw {Kln¡Â, \nco£Ww, \nKa\w, {]iv\]cnlmcw,
NÀ¨ sN¿Â, ]ckv]cw _Ôw, a\Ênem¡Â F¶nhbneqsS ]mZhmÀjnIw F¶ Bibw a\Ênem¡p¶p.
Content
Analysis
Terms : ]mZhmÀjnIw
Facts : 3
amkw IqSpt¼mÄ apXent\mSv ]eni Iq«p¶
coXnbmWv ]mZhmÀjnIw
Concept : ]mZhmÀjnIw
F¶ Bibw
Learning
out come
The student will be able to,
1) Recall related knowledge or information about ratio
2) Describe about the peculiarities of ratio
3) Interpret about the area of ratio
4) Exemplify different situation of ratio
5) Execute the above concept in familiar situation
6) Organize different elements to fit in a situation
7) Judge the appropriateness of the above concept in a
given problem
8) Generate with alternate method of finding ratio
9) Perform artihemetic skill and geometric skill
Pre-requisites
apXÂ, ]eni, ]eni\nc¡v, em`w, \jvSw, Iq«p]eni
F¶nhsb¡pdn¨v Ip«n¡v ap¶dnhpv.
Teaching Learning Resoures
]mZhmÀjnIw
F¶ Bibw DÄs¡mÅp¶ NmÀ«v,BIvänhnäv joäv, aäv ]T\ kma{KlnIÄ
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Class room Interaction procedure
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Expected Pupils Response
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Introduction
A[ym]nI
¢mÊn {]thin¨v Ip«nItfmSv Ipiemt\zjWw \S¯p¶p. XpSÀ¶v ap¶dnhv ]cntim[n¡m\mbn
tNmZy§Ä tNmZn¡p¶p.
km[mcW ]eni
IW¡m¡p¶sX§s\?
ChnsS N
F´mWv ?
P F´mWv
kqNn¸n¡p¶Xv ?
R F´mWv
kqNn¸n¡p¶Xv ?
F¶m Iq«p]eni
IW¡m¡p¶sX§s\?
XpS˦ A[ym]nI Hcp
hÀj¯n F{X amkaps¶v tNmZn¡p¶p.
6 amkw IqSpt¼mÄ ]eni
IW¡m¡p¶ coXnsb F´v ]dbp¶p F¶v tNmZn¡p¶p
F¦n 3 amkw IqSpt¼mÄ ]eni IW¡m¡p¶ cnXnsb F´v F¶v
]dbp¶p F¶v A[ym]nI tNmZn¡p¶p
AXns\ ]mZhmÀjnIw F¶v
]dbpw.
AXmbXv 3 amkw IqSpt¼mÄ
]eni IW¡m¡p¶Xns\ ]mZhmÀjnIw F¶v ]dbpw F¶v A[ym]nI a\Ênem¡n sImSp¡p¶p.
Class room Interaction procedure
Activity
-1
XpS˦v A[ym]nI Zriy
am[ya¯neqsS Hcp {]iv\w {]ZÀin¸n¨p. XpSÀ¶v tNmZymhenIfpw {]ZÀin¸n¨p.
cmap 12500 cq] 8% ]eni
\nc¡n 3 amkt¯¡v ISsaSp¯p. Imemh[n
Ignªv F{X cq] Xncns¨Sbv¡Ww
ISsaSp¯ XpI = þþþþþþþ
]eni \nc¡v = þþþþþþþþþþ
Imemh[n =
þþþþþþþþþþþþþþ
]eni = XpI + ]eni\nc¡v x
hÀjw
Xncn¨Sbvt¡ XpI = XpI
+]eni
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]ZhmÀjnI coXn
3 amkw IqSpt¼mÄ ]eni IW¡m¡n apXent\mSv Iq«p¶ coXnbmWv
]mZhmÀjnI coXn
XpSÀ¶v Ip«nItfmSv
hmbn¡m³ ]dbp¶p. XpSÀ¶v t\m«p _q¡n FgpXnsbSp¡m³ ]dbp¶p.
Activity
-2
hnPb³ ]mZhmÀjnIambn
Iq«p]eni IW¡m¡p¶ _m¦n 6 amkt¯¡v 20,00 cq] 10% ]eni \nc¡n \nt£]n¨p.
Hcp hÀjw Ignªv hnPb\v
F{X cq] XncnsI e`n¡pw.
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I= PNR F¶v Ip«n ]dbp¶p
N = hÀjw
P = apXÂ
R = ]eni \nc¡v
12 amkw F¶v Ip«n ]dbp¶p
AÀ² hmÀjnI coXnsb¶v
Ip«n ]dbp¶p.
Ip«nIÄ BtemNn¡p¶p
Expected Pupils Response
ISsaSp¯ XpI = 125000
cq]
]eni \nc¡v þ 8%
Imemh[n þ 3 amkw
= 3/12=1/4
]eni = 12500 x 1/4 x8/100
= 250 cq]
Xncn¨Sbvt¡ XpI =
12500=250
= 12750 cq]
Ip«nIÄ hmbn¨p Ip«nIÄ
t\m«p _p¡n FgpXm³ ]dªp.
H¶mw ]mZhmÀjnI apXÂ
= 10000 cq]
]eni \nc¡v = 10%
Imemh[n = 6 amkw
H¶mwhmÀjnI ]eni
=10000 x
1/4x 10/100
= 250 cq]
cmw]mZhmÀjnI apXÂ
=10250 cq]
cmw]mZhmÀjnI ]eni
=10250x1/4 x10/100
=256.25 cq]
Xncn¨p e`nt¡ XpI
= 10250 + 256.25
= 10506.25 cq]
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Review & Applicatiopn
]mZ hmÀjnI coXn IW¡m¡p¶Xv F§s\ ?
Follow up Activity
APb³ ]mZhmÀjnIambn Iq«p]eni IW¡m¡p¶
_m¦n Hcp hÀjt¯¡v 25000 cq] 10% ]eni \nc¡n \nt£]n¨p. Hcp hÀjw Ignªv APb\v F{X
cq] XncnsI e`n¡pw.

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